Definition · Vector space
A set with operations and scalar multiplication is a vector space if it is closed under both (C1: ; C2: ) and the following hold for all and scalars :
- 1
- 2
- 3There is with
- 4For each there is with
- 5
- 6
- 7
- 8
→Shortcut
You will almost never verify all eight on an exam. The questions that matter ask you to disprove membership — and that always comes down to closure or the presence of . Look for a concrete counterexample first.
The examples you must recognise
| Space | Elements | Dimension | Zero vector |
|---|---|---|---|
| Column -tuples | |||
| matrices | The zero matrix | ||
| Continuous functions on | infinite | The function | |
| Polynomials of degree | The zero polynomial |
Note the convention: has dimension , with basis . Polynomials of degree exactly do not form a vector space.
Some consequences that follow from the axioms alone: ; forces ; and . Also, if then either or — a fact used constantly in independence arguments.
Worked example
0/3 stepsA set that fails to be a vector space
Is (the first quadrant) a vector space under the usual operations?
Check yourself
T / F
Every vector space contains a zero vector.
Q2
Which of these is not a vector space under the usual operations?